Palindrome in Java GUI

We all know that palindrome is a word or phrase that reads the same backward as forward. Here in this tutorial, we will create a program that can determine if the word inputted is a palindrome or not. Now, let's start this tutorial! 1. Open JCreator or NetBeans and make a java program with a file name of palindrome.java. 2. Import javax.swing package. Hence we will use a GUI (Graphical User Interface) here like the inputting the word.
  1. import javax.swing.*;
3. Before coding in the Main, create first a function named isPalindrome as Boolean that has variable word as string as parameter of it.
  1.    public static boolean isPalindrome(String word) {
  2.     int left  = 0;                 // index of leftmost unchecked char
  3.     int right = word.length() -1;  // index of the rightmost
  4.  
  5.     while (left < right) {         // continue until they reach center
  6.         if (word.charAt(left) != word.charAt(right)) {
  7.             return false;          // if chars are different, finished
  8.         }
  9.         left++;                    // move left index toward the center
  10.         right--;                   // move right index toward the center
  11.     }
  12.  
  13.     return true;                   // if finished, all chars were same
  14. }
4. Initialized your variable in your Main, variable Str as string and make it as an input.
  1. String Str;      
  2. Str = JOptionPane.showInputDialog(null, "Enter String:");
5. Lastly, display the output of the program whether the word is a palindrome or not.
  1. JOptionPane.showMessageDialog(null,"The word " + Str + " is palindrome: " + isPalindrome(Str) );
Take note that isPalindrome(Str) syntax triggers to access the boolean function that will validate the inputted word of variable Str. Output: output Here's the full code of this tutorial:
  1. import javax.swing.*;
  2.  
  3. public class palindrome {
  4.  
  5.  
  6.     public static void main(String[] args) {
  7.    
  8.         String Str;  
  9.      
  10.         Str = JOptionPane.showInputDialog(null, "Enter String:");
  11.  
  12.         JOptionPane.showMessageDialog(null,"The word " + Str + " is palindrome: " + isPalindrome(Str) );
  13.     }
  14.    public static boolean isPalindrome(String word) {
  15.     int left  = 0;                
  16.     int right = word.length() -1;  
  17.  
  18.     while (left < right) {        
  19.         if (word.charAt(left) != word.charAt(right)) {
  20.             return false;      
  21.         }
  22.         left++;                  
  23.         right--;                
  24.     }
  25.  
  26.     return true;                
  27. }
  28. }
Hope this helps! :) Best Regards, Engr. Lyndon R. Bermoy IT Instructor/System Developer/Android Developer/Freelance Programmer If you have some queries, feel free to contact the number or e-mail below. Mobile: 09488225971 Landline: 826-9296 E-mail:[email protected] Visit and like my page on Facebook at: https://www.facebook.com/BermzISware Add and Follow me on Facebook: https://www.facebook.com/donzzsky

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